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Math Help - derivative

  1. #1
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    Post derivative

    Find \frac{dy}{dx} if y=6x^2-3x+2.
    Can someone explain the steps?
    I'm just learning calculus...sorry if seems too basic.
    Thanks!
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    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by live_laugh_luv27 View Post
    Find \frac{dy}{dx} if y=6x^2-3x+2.
    Can someone explain the steps?
    I'm just learning calculus...sorry if seems too basic.
    Thanks!
    use the power rule: if y = x^n, then \frac {dy}{dx} = nx^{n - 1} ....where n is a constant

    just do that for each term. leave the coefficients alone and differentiate the function parts

    can you continue?
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  3. #3
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    Quote Originally Posted by live_laugh_luv27 View Post
    Find \frac{dy}{dx} if y=6x^2-3x+2.
    Can someone explain the steps?
    I'm just learning calculus...sorry if seems too basic.
    Thanks!
    The power rule - An approach to calculus
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  4. #4
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    Post

    so, 6x^2 would become 6x, 3x would become 3, and the 2 is taken away?
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  5. #5
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    no, wait..I think 6x^2 becomes 12x
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    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by live_laugh_luv27 View Post
    so, 6x^2 would become 6x
    no

    3x would become 3, and the 2 is taken away?
    yes

    but remember, it is -3x

    Quote Originally Posted by live_laugh_luv27 View Post
    no, wait..I think 6x^2 becomes 12x
    yes
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  7. #7
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    ok..thanks. It would be 12x-3
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  8. #8
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by live_laugh_luv27 View Post
    ok..thanks. It would be 12x-3
    yes, dy/dx = 12x - 3
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