1. derivative

Find $\displaystyle \frac{dy}{dx}$ if $\displaystyle y=6x^2-3x+2$.
Can someone explain the steps?
I'm just learning calculus...sorry if seems too basic.
Thanks!

2. Originally Posted by live_laugh_luv27
Find $\displaystyle \frac{dy}{dx}$ if $\displaystyle y=6x^2-3x+2$.
Can someone explain the steps?
I'm just learning calculus...sorry if seems too basic.
Thanks!
use the power rule: if $\displaystyle y = x^n$, then $\displaystyle \frac {dy}{dx} = nx^{n - 1}$ ....where $\displaystyle n$ is a constant

just do that for each term. leave the coefficients alone and differentiate the function parts

can you continue?

3. Originally Posted by live_laugh_luv27
Find $\displaystyle \frac{dy}{dx}$ if $\displaystyle y=6x^2-3x+2$.
Can someone explain the steps?
I'm just learning calculus...sorry if seems too basic.
Thanks!
The power rule - An approach to calculus

4. so, $\displaystyle 6x^2$ would become $\displaystyle 6x$, $\displaystyle 3x$ would become 3, and the 2 is taken away?

5. no, wait..I think $\displaystyle 6x^2$ becomes $\displaystyle 12x$

6. Originally Posted by live_laugh_luv27
so, $\displaystyle 6x^2$ would become $\displaystyle 6x$
no

$\displaystyle 3x$ would become 3, and the 2 is taken away?
yes

but remember, it is -3x

Originally Posted by live_laugh_luv27
no, wait..I think $\displaystyle 6x^2$ becomes $\displaystyle 12x$
yes

7. ok..thanks. It would be $\displaystyle 12x-3$

8. Originally Posted by live_laugh_luv27
ok..thanks. It would be $\displaystyle 12x-3$
yes, dy/dx = 12x - 3