Find $\displaystyle \frac{dy}{dx}$ if $\displaystyle y=6x^2-3x+2$.
Can someone explain the steps?
I'm just learning calculus...sorry if seems too basic.
Thanks!
Find $\displaystyle \frac{dy}{dx}$ if $\displaystyle y=6x^2-3x+2$.
Can someone explain the steps?
I'm just learning calculus...sorry if seems too basic.
Thanks!
use the power rule: if $\displaystyle y = x^n$, then $\displaystyle \frac {dy}{dx} = nx^{n - 1}$ ....where $\displaystyle n$ is a constant
just do that for each term. leave the coefficients alone and differentiate the function parts
Find $\displaystyle \frac{dy}{dx}$ if $\displaystyle y=6x^2-3x+2$.
Can someone explain the steps?
I'm just learning calculus...sorry if seems too basic.
Thanks!