can you help me with this calculus problem?
here it is
integral of dy/sqrt[(11*y^2)+5]
i use algebraic substitution but i cant come up with an answer.. thnx in advance..
oh.. i did not get that one.. can u explain the process.. how did you get off the constant??
i tried it with substitution but i just cant get it.. it will just re turn to the same equation but the sqrt is at the numerator..
ot:
how can u do the image something up there?? the image of the Y=sqrt of5/sqrt of 11 *t??
oh.. im sorry but where did you get the sqrt of 5/sqrt of 11*t
did you do something to it?? or you just let y be equal to that constant??
i mean i get the lat part cause its simple algebra but the first part??
ok this is easy to differetiate
then after this one, the derivative of y
am i right.. dont we need to substitute dy in the numerator since the original equation goes like this
so im really wonderin were did you get
cant we let
then it will become
then getting dy we will just use the formula integral of u/v is vdu-udv all over v^2 ayt?? that's the first method i did but i got confused.. then when you let y be equal to sqrt of 5 over 11 i also got confused..
yes i can, by trigonometric substitution..
ive already solved it but using algebraic substitution.. its simple.. but i dont know if its correct....
here is what i did.. from the original equation
i let
then
i get the dy.. and it become
then i substitute the values of dy and t to the original equation and i get..
then the answer will be
am i correct??
yes i get it.. i let the denomenator to be equal to "t" ,then i get the value of "y" in terms of "t".. then get the derivative of "y"...
so the original equation is
i just substitute the value of dy and the denomenator so that i can integrate it easily.. then i came up with my answer.. so y do i still need to differentiate my answer??