The region between the graphs of y=x^2 and y=4x is rotated around the line y=16. The volume of the resulting solid is i thought it would be the definite integral |16 | pi[((x^2)^2)-((4x)^2)]dx |0 but thats not right
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Originally Posted by dat1611 The region between the graphs of y=x^2 and y=4x is rotated around the line y=16. The volume of the resulting solid is i thought it would be the definite integral |16 | pi[((x^2)^2)-((4x)^2)]dx |0 but thats not right did you make a sketch? $\displaystyle V = \pi \int_a^b [R(x)]^2 - [r(x)]^2 \, dx$ $\displaystyle R(x) = 16-x^2 $ $\displaystyle r(x) = 16-4x$ limits of integration are from $\displaystyle a = 0$ to $\displaystyle b = 4$
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