# volume formed by rotating the region

• Aug 7th 2009, 07:28 AM
dat1611
volume formed by rotating the region
Find the volume formed by rotating the region enclosed by:
x=9y and y^3=x with y>=0
can anyone help with this
• Aug 7th 2009, 07:53 AM
Failure
Quote:

Originally Posted by dat1611
Find the volume formed by rotating the region enclosed by:
x=9y and y^3=x with y>=0
Well, the curves intersect at $(-3,-27), (0,0)$ and $(3,27)$ therefore:
$V=\int\limits_0^3\pi \left[(9y)^2-(y^3)^2\right]\, dy$
$V=\int\limits_0^{27}2\pi x(x^{1/3}-\tfrac{1}{9}x)\,dx$
Hopefully they are the same ( $V\approx 1308.69774$). (Rofl)