Use substitution to evaluate the integral: the integral of Π/4 to 3Π/4 of cot x dx So far, I have that u = cot x , du = -csc x squared, and dx = -1/(cscx squared) Thanks for any help
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Originally Posted by turtle Use substitution to evaluate the integral: the integral of Π/4 to 3Π/4 of cot x dx So far, I have that u = cot x , du = -csc x squared, and dx = -1/(cscx squared) Thanks for any help The integral, Let, . Thus, Thus,
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