Find the equation of the tangents to the curve y=2x^2+3 that passes through the following:
a) point (2,3)
my work is below:
y=2x^2+3 PP(2,3)
y'=4x
at x=2
f'(2)=4(2)
=8
y=8x+b
3=8(2)+b
b=-13
y=8x-13
Can someone please verify or check to see if my answer or the way that i did it is correct? Thanks
the question asked for the lines tangent to the curve that pass thru the point (2,3) which is not on the curve.
point on the curve ...
slope between the point on the curve and the point (2,3) ...
tangent slope =
,
point on the curve ... (0,3) , slope = 0
the tangent line that passes through (2,3) is y = 3
point on the curve ... (4,35), slope = 16
the tangent line that passes through (2,3) is y = 16x - 29