Find the equation of the tangents to the curve y=2x^2+3 that passes through the following:

a) point (2,3)

my work is below:

y=2x^2+3 PP(2,3)

y'=4x

at x=2

f'(2)=4(2)

=8

y=8x+b

3=8(2)+b

b=-13

y=8x-13

Can someone please verify or check to see if my answer or the way that i did it is correct? Thanks