if Bernstein polynomials defined by

how I can integrate it

this is my work

since the summation is the Taylor series of

my work is correct but I think I can't reach the true answer if I continue

the answer is

Thanks very much .

Printable View

- Aug 6th 2009, 10:39 AMAmerhow to integrate this ??
if Bernstein polynomials defined by

how I can integrate it

this is my work

since the summation is the Taylor series of

my work is correct but I think I can't reach the true answer if I continue

the answer is

Thanks very much . - Aug 6th 2009, 11:00 AMBruno J.
Why is there an in what you say is the answer? Certainly the answer is not independent of the bounds . Perhaps that is the indefinite integral?

- Aug 6th 2009, 11:41 AMAmer
- Aug 6th 2009, 12:27 PMBruno J.
Have you tried induction on ? It might very well work with the right argument. For instance you have

Induction and integration by parts might work from there... - Aug 6th 2009, 12:47 PMAmer
- Aug 7th 2009, 12:45 PMAmer
any hints to integrate

Thanks - Aug 9th 2009, 02:56 AMsimplependulum

integration by parts

Sub

therefore , the integral =

- Aug 9th 2009, 09:27 AMAmer
- Aug 9th 2009, 09:14 PMsimplependulum