if Bernstein polynomials defined by

how I can integrate it

this is my work

since the summation is the Taylor series of

my work is correct but I think I can't reach the true answer if I continue

the answer is

Thanks very much .

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- Aug 6th 2009, 09:39 AMAmerhow to integrate this ??
if Bernstein polynomials defined by

how I can integrate it

this is my work

since the summation is the Taylor series of

my work is correct but I think I can't reach the true answer if I continue

the answer is

Thanks very much . - Aug 6th 2009, 10:00 AMBruno J.
Why is there an in what you say is the answer? Certainly the answer is not independent of the bounds . Perhaps that is the indefinite integral?

- Aug 6th 2009, 10:41 AMAmer
- Aug 6th 2009, 11:27 AMBruno J.
Have you tried induction on ? It might very well work with the right argument. For instance you have

Induction and integration by parts might work from there... - Aug 6th 2009, 11:47 AMAmer
- Aug 7th 2009, 11:45 AMAmer
any hints to integrate

Thanks - Aug 9th 2009, 01:56 AMsimplependulum

integration by parts

Sub

therefore , the integral =

- Aug 9th 2009, 08:27 AMAmer
- Aug 9th 2009, 08:14 PMsimplependulum