Find c0 such that the area of the region enclosed by the parabolas y=x2c2 and y=c2x2 is 340. c= can someone solve this
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Originally Posted by dat1611 Find c0 such that the area of the region enclosed by the parabolas y=x2c2 and y=c2x2 is 340. c= can someone solve this sketch a graph and note the region is symmetrical to both axes, making the area in each quadrant the same ... $\displaystyle \int_0^c c^2 - x^2 \, dx = \frac{340}{4}$ solve for c
i still dont get it
look at the graph ... the top graph is $\displaystyle y = c^2 - x^2$ the bottom graph is $\displaystyle y = x^2 - c^2$ the x-intercepts for both are $\displaystyle \pm c$
so whats the answer
Originally Posted by dat1611 so whats the answer I set it up for you in my first post ... work it out and see what you get for c.
solve for c im not sure how to solve for c here
Originally Posted by dat1611 solve for c im not sure how to solve for c here evaluate the definite integral using the Fundamental Theorem of Calculus ... set the result equal to 340/4 and solve for c.
ok i got it c=5.03311
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