# Thread: region enclosed by parabolas

1. ## region enclosed by parabolas

Find c0 such that the area of the region enclosed by the parabolas y=x2c2 and y=c2x2 is 340.
c=
can someone solve this

2. Originally Posted by dat1611
Find c0 such that the area of the region enclosed by the parabolas y=x2c2 and y=c2x2 is 340.
c=
can someone solve this
sketch a graph and note the region is symmetrical to both axes, making the area in each quadrant the same ...

$\int_0^c c^2 - x^2 \, dx = \frac{340}{4}$

solve for c

3. i still dont get it

4. look at the graph ...

the top graph is $y = c^2 - x^2$

the bottom graph is $y = x^2 - c^2$

the x-intercepts for both are $\pm c$

6. Originally Posted by dat1611
I set it up for you in my first post ... work it out and see what you get for c.

7. solve for c

im not sure how to solve for c here

8. Originally Posted by dat1611

solve for c

im not sure how to solve for c here
evaluate the definite integral using the Fundamental Theorem of Calculus ... set the result equal to 340/4 and solve for c.

9. ok i got it
c=5.03311