Assume that the equation defiines y as a function of x. Use implicit diff. to find dy/dx. $\displaystyle 2xy-y^2=1$
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I'm getting $\displaystyle \frac{y}{y-x}$ Is this correct? Thanks
Originally Posted by Darkhrse99 Assume that the equation defiines y as a function of x. Use implicit diff. to find dy/dx. $\displaystyle 2xy-y^2=1$ $\displaystyle 2y + 2xy' - 2yy' = 0$ $\displaystyle y'(2x - 2y) = -2y$ $\displaystyle y' = \frac{-y}{x - y}$
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