# Use implicit differentiation to find dy/dx. Can I get my answer checked please?

• Aug 5th 2009, 10:49 AM
Darkhrse99
Use implicit differentiation to find dy/dx. Can I get my answer checked please?
Assume that the equation defiines y as a function of x. Use implicit diff. to find dy/dx.

$2xy-y^2=1$
• Aug 5th 2009, 10:51 AM
Darkhrse99
I'm getting $\frac{y}{y-x}$ Is this correct?

Thanks
• Aug 5th 2009, 11:10 AM
janvdl
Quote:

Originally Posted by Darkhrse99
Assume that the equation defiines y as a function of x. Use implicit diff. to find dy/dx.

$2xy-y^2=1$

$2y + 2xy' - 2yy' = 0$

$y'(2x - 2y) = -2y$

$y' = \frac{-y}{x - y}$