Assume that the equation defiines y as a function of x. Use implicit diff. to find dy/dx.

$\displaystyle 2xy-y^2=1$

- Aug 5th 2009, 10:49 AMDarkhrse99Use implicit differentiation to find dy/dx. Can I get my answer checked please?
Assume that the equation defiines y as a function of x. Use implicit diff. to find dy/dx.

$\displaystyle 2xy-y^2=1$ - Aug 5th 2009, 10:51 AMDarkhrse99
I'm getting $\displaystyle \frac{y}{y-x}$ Is this correct?

Thanks - Aug 5th 2009, 11:10 AMjanvdl