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Math Help - Integrals, #2

  1. #1
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    Integrals, #2

    hi
    can you solve the integral in the attachment ?? ..
    i integrated it by parts 4 times !! ..
    I started it with :
    u = arctan x ---> du = [1/(1+x^2)] dx
    dv = arcsin dx ---> v = by parts it self

    i didnt try to get u = (arctan x)(arcsin x)

    Attached Thumbnails Attached Thumbnails Integrals, #2-integral-1.jpg  
    Last edited by TWiX; August 5th 2009 at 10:42 AM. Reason: arctan ---> arctan x
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  2. #2
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    Quote Originally Posted by TWiX View Post
    hi
    can you solve the integral in the attachment ?? ..
    i integrated it by parts 4 times !! ..
    I started it with :
    u = arctan x ---> du = [1/(1+x^2)] dx
    dv = arcsin dx ---> v = by parts it self

    i didnt try to get u = (arctan x)(arcsin x)

    The answer does not appear to be elementary. Where has the question come from?
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  3. #3
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    You would not be able to use U-Subst as using either arcsin x, or arctan x as dV would cause never ending loop because the integral of arcsin or arctan contains arcsin or arctan in the answer. If this had limits I'd tell you to approximate using one of the approximation rule.
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