1. ## Camn I get my answer checked out?

I need to take the derivative of $Y=(1+ln7x)^3$

I get $3(1+ln7x)^2 ( 1+\frac{7}{x})$

Is this correct?

Thanks

2. Originally Posted by Darkhrse99
I need to take the derivative of $Y=(1+ln7x)^3$

I get $3(1+ln7x)^2 ({\color{red}1+\frac{7}{x}})$

Is this correct?
Almost, but not quite, because the derivative of $1+\ln(7x)$ happens to be $0+\frac{1}{7x}\cdot 7=\frac{1}{x}$, and not what you thought it is.

3. check the attachment ..

4. So it's $\frac{3}{x}(1+ln7x)^2$?

5. Originally Posted by Darkhrse99
So it's $\frac{3}{x}(1+ln7x)^2$?
right

6. Correct ..
but write ln(7x) with brackets ..