Interpret the limit as the slope of the tangent line to a curve at a specific point after you evaluate the limit.
lim[(1+h)^(1/6)-1]/h
h->0
I evaluated the limit to be
M_t=1/6 to y=x^(1/6) but I am having trouble finding the x co-ordinate.
The answer in the back says:
M_t=1/6 to y=x^(1/6) at x=1
how did they get x=1?