Interpret the limit as the slope of the tangent line to a curve at a specific point after you evaluate the limit.

lim[(1+h)^(1/6)-1]/h

h->0

I evaluated the limit to be

M_t=1/6 to y=x^(1/6) but I am having trouble finding the x co-ordinate.

The answer in the back says:

M_t=1/6 to y=x^(1/6)at x=1

how did they get x=1?