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Thread: Can someone check my answer please?

  1. #1
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    Can someone check my answer please?

    Take the derivative of $\displaystyle 5x^2e^3x$

    I got $\displaystyle 10xe^3x(2x+3)$ The X afeter the 3 are suppose to be with the 3 and not lower then the 3.



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    Quote Originally Posted by Darkhrse99 View Post
    Take the derivative of $\displaystyle 5x^2e^3x$

    I got $\displaystyle 10xe^3x(2x+3)$ The X afeter the 3 are suppose to be with the 3 and not lower then the 3.



    Thanks
    $\displaystyle f(x) = 5x^2e^{3x}$

    Using the product rule

    $\displaystyle u = 5x^2 \: , \: u' = 10x$

    $\displaystyle v = e^{3x} \: , \: v' = 3xe^{3x}$

    $\displaystyle f'(x) = u'v + v'u$

    $\displaystyle f'(x) = 10xe^{3x} + 15x^3e^{3x} = 5xe^{3x}(2+3x^2)$
    Last edited by e^(i*pi); Aug 5th 2009 at 08:50 AM. Reason: correcting a poor minus sign
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  3. #3
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    Quote Originally Posted by Darkhrse99 View Post
    Take the derivative of $\displaystyle 5x^2e^3x$
    I got $\displaystyle 10xe^3x(2x+3)$ The X afeter the 3 are suppose to be with the 3 and not lower then the 3.
    If you have more than one character in an exponent, set off the whole exponent in braces.
    [tex]x^{3x}[/tex] gives $\displaystyle x^{3x} $ instead of $\displaystyle x^3x$.
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