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Math Help - Can I get help finding the derivative?

  1. #1
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    Can I get help finding the derivative?

    t^3cost-13tsint-13cost



    Thanks
    Jason
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  2. #2
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    Quote Originally Posted by Darkhrse99 View Post
    t^3cost-13tsint-13cost



    Thanks
    Jason
    The derivative is found using relatively straight-forward methods (Product Rule and Summing Rule). Can you show your work, so that we can see what you've done?
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  3. #3
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    I came up with -3t^2sint-13cost+13sint

    Is this correct?
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  4. #4
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    Quote Originally Posted by Darkhrse99 View Post
    I came up with -3t^2sint-13cost+13sint

    Is this correct?
    Not quite. You do not seem to have applied the product rule correctly.

    I get the following (for the the first two terms you need to apply the product rule)

    \begin{array}{l}<br />
(t^3\cos t-13t\sin t-13\cos t)'\\<br />
\quad =3t^2\cdot\cos t+t^3\cdot(-\sin t)-13\cdot \sin t-13t\cdot\cos t-13(-\sin t)\\<br />
\quad = 3t^2\cos t -t^3\sin t-13t\cos t<br />
\end{array}
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