(1 pt) Find the area between the curves: y1 = x^3 - 11 x^2 + 28 x and y2 = -x^3 + 11 x^2 - 28 x so x = 0, 4, 7 y1 is the larger function i think but im not sure how to do the the integral when i have 3 points
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Originally Posted by dat1611 (1 pt) Find the area between the curves: y1 = x^3 - 11 x^2 + 28 x and y2 = -x^3 + 11 x^2 - 28 x so x = 0, 4, 7 y1 is the larger function i think but im not sure how to do the the integral when i have 3 points sketch or draw the graph on your calculator ... y1 > y2 on (0,4) y2 > y1 0n (4,7) set up the two integrals to find the area.
so its |4 | y1-y2 |0 + |7 | y2-y1 |4
(1 pt) Find the area between the curves: y1 = x^3 - 11 x^2 + 28 x and y2 = -x^3 + 11 x^2 - 28 x so x = 0, 4, 7 y1 is the larger function i think but im not sure how to do the the integral when i have 3 points See this picture
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