how do you find out if e^(3x) is divergent and what to?
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Originally Posted by Lupus how do you find out if e^(3x) is divergent and what to? That is not a question, please try again posting all of the question next time. CB
I see no bounds and I don't know if we're talkin' about an improper integral. Please, give full statement of your problem.
Originally Posted by Krizalid I see no bounds and I don't know if we're talkin' about an improper integral. Please, give full statement of your problem. The thread title implies we are differentiating not integrating in this case!? CB
Yes but, why talkin' about convergence then.
Originally Posted by Krizalid Yes but, why talkin' about convergence then. Indeed!? CB
sorry. the full question is: Determine if the following integral is convergent or divergent and if it is convergent find its value (it is an integral between the limits -infinity and 0) e^3x dx.
Originally Posted by Lupus sorry. the full question is: Determine if the following integral is convergent or divergent and if it is convergent find its value (it is an integral between the limits -infinity and 0) e^3x dx. This is asking if the following limit exists $\displaystyle \lim_{a \to \infty} \int_{-a}^0 e^{3x}\; dx$ The definite integral you should be able to write down intermediatly so what do you think? CB
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