Thread: Partial Differentiation

Hi guys could you please help me with this question-


For an arbitrary function f = f(u, v) show that

1/x(df/dx) + 1/y(df/dy) = 4(df/du)

where u = x^2 + y^2, v = x^2 − y^2,

x not = 0 and y not = 0

Originally Posted by rologolfer

Hi guys could you please help me with this question-


For an arbitrary function f = f(u, v) show that

1/x(df/dx) + 1/y(df/dy) = 4(df/du)

where u = x^2 + y^2, v = x^2 − y^2,

x not = 0 and y not = 0

By the chain rule, .
Does this help?

Thanks a lot, thats great!