An objects accleration function is given by a(t)=10t+4, v(0), is 5 and the objects initial position,s(o) is 12. Find S(t)?
I'm not sure where to start this one.
Follow Math Help Forum on Facebook and Google+
v(t) = integral[ (a(t)dt]
v(t) = 5t^2 + 4t +C
Since v(0) = 5
C = 5
v(t) = 5t^2 + 4t + 5
Now s(t) = integral[v(t)dt] so repeat the process
View Tag Cloud