An objects accleration function is given by a(t)=10t+4, v(0), is 5 and the objects initial position,s(o) is 12. Find S(t)? I'm not sure where to start this one. Thanks
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v(t) = integral[ (a(t)dt] v(t) = 5t^2 + 4t +C Since v(0) = 5 C = 5 v(t) = 5t^2 + 4t + 5 Now s(t) = integral[v(t)dt] so repeat the process
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