D ' (x) = 7/(x+5)
D(x) = 7ln(x+5) + C
taking the normal body temp to be 37.5 (Centigrade) then D(1) = 39.8
D(1) = 7ln(6) + C = 39.8 which yields C= 39.8 - 7ln(6)
D(x) = 7ln(x+5) + 39.8 - 7ln(6)
The rate of change in a person's body temp, with respect to the dosage of X milligrams of a drug, is given by D Prime of x= One milligram raises the body temp 2.3* C. Find the function
Where do I start with this problem?
Thanks
If D(x) represents the persons body temperature neither one is right
as D(0) = 13.6 deg in one case and 1 deg in the other--in either case
the patient is long dead.
If D(x) represents the temp above normal body temp
D(x) = 7ln(x+5) + C
D(1) = 7ln(6) +C = 2.3
in which case C = -10.2
D(x) = 7ln(x+5) - 10.2