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Math Help - Not sure if this is correct...

  1. #1
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    Not sure if this is correct...

    Okay well I have a definite integral with a square root and u of x-1, with x on the outside and a,b values 1,3.

    I changed (sqrt)x-1 to (x-1)^1/2 and divided the x by x to get u' or 1, leaving an x on the outside of the integral. I also changed the a,b values to 0,2. and came out with the answer 3x/2 (x-1)^3/2 before continuing is this correct? I just would like to make sure because I have never gotten a problem like this.
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  2. #2
    Member McScruffy's Avatar
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    Quote Originally Posted by radioheadfan View Post
    Okay well I have a definite integral with a square root and u of x-1, with x on the outside and a,b values 1,3.

    I changed (sqrt)x-1 to (x-1)^1/2 and divided the x by x to get u' or 1, leaving an x on the outside of the integral. I also changed the a,b values to 0,2. and came out with the answer 3x/2 (x-1)^3/2 before continuing is this correct? I just would like to make sure because I have never gotten a problem like this.
    Is this the integral that you are trying to sovle?

    \int_{1}^{3}x\sqrt{x-1}dx

    If so, I would let u=x-1 like you said, then sub. u+1=x back in for x. Then integrate from there, after changing the limits like you said.
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  3. #3
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    Quote Originally Posted by McScruffy View Post
    Is this the integral that you are trying to sovle?

    \int_{1}^{3}x\sqrt{x-1}dx

    If so, I would let u=x-1 like you said, then sub. u+1=x back in for x. Then integrate from there, after changing the limits like you said.
    okay so I was right, got the same answer
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