Hey guys, I've been staring at this problem for quite some time and not really sure where to start.

http://img26.imageshack.us/img26/6676/question13.jpg

Any assistance would be greatly appreciated. Thanks.

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- August 3rd 2009, 02:26 AMenjamProof question
Hey guys, I've been staring at this problem for quite some time and not really sure where to start.

http://img26.imageshack.us/img26/6676/question13.jpg

Any assistance would be greatly appreciated. Thanks. - August 3rd 2009, 05:19 AMOpalg
Start by guessing what ought to be. Differentiating under the integral sign would suggest that .

Now see if you can justify that guess by doing as the hint suggests and using the definition of the derivative. First, note that . Then , so that .

The idea now is to find a bound for that last integral. The other factor will then ensure that the expression on the left side of the inequality goes to 0 as , which will show that is differentiable at .

To get a bound on that integral, let d be the distance from to the interval [0,1] (you are told that , so you know that d>0), and choose z close enough to to ensure that the distance from z to [0,1] is greater than d/2. That will give you a lower bound on the denominator of the integrand; and the fact that h is continuous means that it is bounded on [0,1], so that gives you an upper bound for the numerator.