locate the stationary point(s) on this curve: y=x^3 - 2lnx^3 i keep on finding (1,1), which apparently is so wrong. helpful hints?
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Originally Posted by furor celtica locate the stationary point(s) on this curve: y=x^3 - 2lnx^3 i keep on finding (1,1), which apparently is so wrong. helpful hints? At a stationary point, So the stationary point is .
Last edited by alexmahone; Aug 2nd 2009 at 09:35 PM.
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