locate the stationary point(s) on this curve:

y=x^3 - 2lnx^3

i keep on finding (1,1), which apparently is so wrong. helpful hints?

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- August 2nd 2009, 09:10 PMfuror celticastationary point
locate the stationary point(s) on this curve:

y=x^3 - 2lnx^3

i keep on finding (1,1), which apparently is so wrong. helpful hints? - August 2nd 2009, 09:24 PMalexmahone