locate the stationary point(s) on this curve:

y=x^3 - 2lnx^3

i keep on finding (1,1), which apparently is so wrong. helpful hints?

Printable View

- Aug 2nd 2009, 10:10 PMfuror celticastationary point
locate the stationary point(s) on this curve:

y=x^3 - 2lnx^3

i keep on finding (1,1), which apparently is so wrong. helpful hints? - Aug 2nd 2009, 10:24 PMalexmahone