Find polynomials p(x) and q(x) such that f(x) = p(x)/q(x) has vertical asymptotes x=-2, x=5, horizontal asymptote y=1 and f(-1) = f(4)=0.
Any hints on how to do this?
Does that mean we have f(x) =
So p(-1) = 0
p(4) = 0
and p(x)/q(x) has a local max at (1.5, almost(1))?
So the derivative of at 1.5 = 0? (1.5 because it's half-way between -2 and 5..
Is that how I'm supposed to solve for p(x)?
For vertical asymptotes, the denominator must go to zero forFind polynomials and such that: . has vertical asymptotes ,
horizontal asymptote and
. . Hence: .
So we have: .
For the horizontal asymptote, the function goes to 1 as
. . Hence, has the same degree as , and has a leading coefficient of 1.
That is: .
And we have: .
Add  and : .
Edit: Ah ... DeMath beat me to it.
Oh well, my explanation is slightly different.