What is the area of the surface generated wheny=((x^3)/6)+((1)/2x), from x=1, to x=3?
Last edited by chevy900ss; Aug 2nd 2009 at 03:08 PM.
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You really need to give more information than that. What object are we finding the surface area of?
ok i rewrote the question.
Ok I think you are after the following equation where can you find ?
derivative=((x^2)/2)+((1)/-2x^2)
using that equation i get 214pie/9. Is that right?
Originally Posted by chevy900ss derivative=((x^2)/2)+((1)/-2x^2) Not quite but a good effort.
Last edited by pickslides; Aug 2nd 2009 at 03:56 PM. Reason: typo
how is it -((2)/(x^2). I thought ((1)/2x) is the same as ((x^-1)/2) where you bring the (-1) down front and subtract (1) from the exponent which gives you -((x^-2)/2). Which is -1/2x^2
After a second look you are correct Sorry about that my friend!
Originally Posted by chevy900ss using that equation i get 214pie/9. Is that right? Ok is this right using that derivative?
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