Find the length of a curve given by:
y= (x^4)/4 + 1/8x^2 for 1<x<3
I understand length of curves, but I am confused how to find the square root of:
sqr(x^6 + 1/2 x^4 + 1/16 x^2 + 1)
help? Am I writing this term wrong in the first place?
thanks!
Find the length of a curve given by:
y= (x^4)/4 + 1/8x^2 for 1<x<3
I understand length of curves, but I am confused how to find the square root of:
sqr(x^6 + 1/2 x^4 + 1/16 x^2 + 1)
help? Am I writing this term wrong in the first place?
thanks!
I know how these problems are rigged to work.
They are quite artifical and what happens is the +1 changes a -.5 to a +.5
Hence MY guess is that the second power is -2 not +2
y= (x^4)/4 + 1/8x^{-2} for 1<x<3
I GUESS you meant to put 1/(8x^2), which I know works.
But your math showed that you wanted (1/8)x^2.
Hmm... how did you end up with the +1 at the end of the equation, I just get sqrt. (x^6 + 1/2 x^4 + 1/16x^2).
Anyway, it'd equal:
x^3 + sqrt. 1/2 x^2 + 1/4 x
You would then integrate this to get:
x^4 / 4 + x^3 / 3sqrt(1/2) + x^2 / 8
Length between 3 and 1 would equal:
(20.25 + 12.73 + 1.13) - (0.25 + 0.47 + 0.13)
= 33.26