The answer is

I've tried plugging in 2 for x and 1 for x, but I'm not coming up with the answer.

Thanks

Jason

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- Jul 29th 2009, 01:48 PMDarkhrse99I need help finishing this problem.

The answer is

I've tried plugging in 2 for x and 1 for x, but I'm not coming up with the answer.

Thanks

Jason - Jul 29th 2009, 01:50 PMANDS!

Should it be this? - Jul 29th 2009, 02:03 PMDarkhrse99
- Jul 29th 2009, 02:07 PMskeeter
- Jul 29th 2009, 02:14 PMANDS!
Well

is

And agreed. That expression evaluated on those bounds can't be the answer you've got; unless this isn't the full problem. - Jul 29th 2009, 02:19 PMDarkhrse99
The original problem is find the arc length of the indicated interval.

- Jul 29th 2009, 02:41 PMANDS!
Whoa. That is markedly different than what you had. What you had simply said "evaluate the integral from 1 to 2". Which is what we're doing when finding arc-length.

So we have an equation of the form

is equal to the arc-legth of from to .

So from your equation we need to find the derivative of:

Which is equal to:

Plugging this into our equation for arc length yields:

Can you distribute that squared and go from there? - Jul 29th 2009, 02:47 PMskeeter
- Jul 29th 2009, 02:54 PMDarkhrse99
Got it guys! Sorry for the confusion.