Hi all,

I am stuck at the end of this.

Find the minimum value of the curve y = x⁴ - 2x² + 3 in the domain -3 ≤ x ≤ 3.

y = x⁴ - 2x² + 3

y’ = 4x³ - 4x

stationary points where y’ = 0

4x³ - 4x = 0

4(x³ - x) = 0

Stuck here

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- Jul 29th 2009, 06:32 AMJoelFind a minimum value
Hi all,

I am stuck at the end of this.

Find the minimum value of the curve y = x⁴ - 2x² + 3 in the domain -3 ≤ x ≤ 3.

y = x⁴ - 2x² + 3

y’ = 4x³ - 4x

stationary points where y’ = 0

4x³ - 4x = 0

4(x³ - x) = 0

Stuck here - Jul 29th 2009, 06:38 AMsongoku
4(x^3 - x) = 0

4x(x^2 - 1) = 0

Can you continue? ^^ - Jul 29th 2009, 06:53 AMHallsofIvy