What would happen if

X^(1/3 - 1/3)

I know that X^(1/3 - 2/3) = X^(-1/3)

What would happen then. It can't be 0/3.

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- Jul 28th 2009, 04:47 PM #1

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- Jul 28th 2009, 04:51 PM #2

- Jul 28th 2009, 04:56 PM #3

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- Jul 28th 2009, 04:59 PM #4

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- Jul 28th 2009, 10:10 PM #5

- Jul 29th 2009, 05:13 AM #6

- Jul 29th 2009, 05:37 AM #7
The problem I intend to propose is the following: for real or complex $\displaystyle x$ and real or complex $\displaystyle a$ is...

$\displaystyle x^{a - a} = \frac {x^{a}}{x^{a}}$

... that means a number devided by himself. Well!... and whay is not...

$\displaystyle \frac {x^{a}}{x^{a}} = 1$

... for all $\displaystyle x$?...

Kind regards

$\displaystyle \chi$ $\displaystyle \sigma$