I think i found the bottom one, 2n+3 the only way i can see the top one is in a recursive but i need a closed form, can anyone give me some hints on how to look at it...
Find a formula for sn, n 1. , , , , , , ...
The numerator is $\displaystyle n! = n\cdot (n-1)\cdot (n-2) \cdot \dots \cdot 3 \cdot 2 \cdot 1$.
So $\displaystyle t_n = \frac{n!}{2n + 3}$
$\displaystyle S_n = \sum_{i = 1}^n \frac{n!}{2n + 3}$.
If this was an infinite series, it would diverge btw. But since it's finite, that's a bit trickier...