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Math Help - Resistance produced by three conductors

  1. #1
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    Resistance produced by three conductors

    Iím not sure how to start this problem (See attachment). I have to differentiate R with respect to R1 but the equation given is in the form 1/R, not R. How should I rearrange this function to make R the subject of this equation.

    Any help showing working would be a great help.

    Thanks, Daddy_Long_Legs
    Attached Thumbnails Attached Thumbnails Resistance produced by three conductors-question-2.jpg  
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  2. #2
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    I think if R=1/R1+1/R2+1/R3, the 1/R=1/(1/R1+1/R2+1/R3).
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  3. #3
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    1/r = 1/r1 + 1/r2 + 1/r3

    1/r = {(r1 r2) + (r1 r3) + (r1 r2)} / {r1 r2 r3}

    r = ...
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  4. #4
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    So R would equal 1/{(r1 r2) + (r1 r3) + (r1 r2)} / {r1 r2 r3}?
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  5. #5
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    Yes, and 1/{(r1 r2) + (r1 r3) + (r1 r2)} / {r1 r2 r3} will be equal to {r1 r2 r3} / {(r1 r2) + (r1 r3) + (r1 r2)}
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  6. #6
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    Thanks songoku,

    I just wasn't too sure of my algebra. I should be able to finish the problem.
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  7. #7
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    You're welcome ^^
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