Use mathematical induction to prove that 1^2 + 2^2 + 3^2.... + n^2 = (n(n+1)(2n+1))/6 thanks!
Last edited by s0urgrapes; Jul 26th 2009 at 02:39 PM.
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Originally Posted by s0urgrapes Use mathematical induction to prove that 1^2, 2^2, 3^2....n^2 = (n(n+1)(2n+1))/6 It should be 1^2+ 2^2+ 3^2+....+n^2 = (n(n+1)(2n+1))/6
It's obviously true for n=1. Assume is true for some k>1. then
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