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Math Help - Calculus Help Needed!

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    Calculus Help Needed!

    Find y'(x) and y''(x) for y=x*sin(4x)
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  2. #2
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    Quote Originally Posted by asnxbbyx113 View Post
    Find y'(x) and y''(x) for y=x*sin(4x)
    Use the chain rule:
    y' = 1 \cdot sin(4x) + x \cdot cos(4x) \cdot 4 = 4xcos(4x) + sin(4x)

    y'' = 4 (1 \cdot cos(4x) + x \cdot -sin(4x) \cdot 4) + cos(4x) \cdot 4 = 8 cos(4x) - 16xsin(4x)

    -Dan
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    Thank You So Much!
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