Th question is :

Consider the region bounded byy= cos(x),y= 0,x= 0, andx= /4. Rotate the region around thex-axis. Sketch the region. Write an integral giving the volume of the solid. Give your answer using the form below.

What i got was that A=0 B=pi/4 and the integral is pi*cos(x)^2 dx

Im not sure if this is correct can anyone double check me please? thanks