1. ## [SOLVED] improper integral

question:$\displaystyle \int_{-\infty}^{-1} \frac{1}{\sqrt{2-w}}dw$
work:$\displaystyle \lim_{t\to-\infty}\int_t^{-1}\frac{1}{\sqrt{2-w}} \, dw$ I used u substitution with $\displaystyle u=2-w$ leaving me with $\displaystyle \lim_{t\to-\infty}2\sqrt{2-w}$ from -1 to t
answer: diverges. Sorry, delete this post

2. Originally Posted by superdude
question:$\displaystyle \int_{-\infty}^{-1} \frac{1}{\sqrt{2-w}}dw$
$\displaystyle \int \frac{1}{\sqrt{2-w}}dw = -2 \sqrt{2-w}$

So evaluated as a definite integral between $\displaystyle - \infty$ and $\displaystyle -1$ the integral does not converge.

3. Originally Posted by superdude
question:$\displaystyle \int_{-\infty}^{-1} \frac{1}{\sqrt{2-w}}dw$
work:$\displaystyle \lim_{t\to-\infty}\int_t^{-1}\frac{1}{\sqrt{2-w}} \, dw$ I used u substitution with $\displaystyle u=2-w$ leaving me with $\displaystyle \lim_{t\to-\infty}2\sqrt{2-w}$ from -1 to t
answer: diverges. Sorry, delete this post
Once a reply has been given to a question it is policy not to delete the thread.