I've attached a rough sketch of the situation.
First calculate the distances:
is the distance which is travelled by canoe.
is the distance to jog.
Now use the formula to calculate the time needed:
This is a function of t in x. Calculate the first derivative:
. To get the minimum t'(x) = 0:
. Square the equation and multiply by (1+x≤). You'll get
The only possible result is x = 0.75
Plug in this value in t(x) and you get the minimum time: 0.86666 ... = 13/15 hours = 52 minutes.