# Thread: help.. . concavity curve sketching

1. ## help.. . concavity curve sketching

Sketch a possible graph with the following characteristics

dont even know where to start. . . any help is appreciated.

thanks

Jordan

2. If $f'(-2)=f'(2)=0$ then we can consider $f'(x)=a(x^2-4)$

Then $f(x)=\frac{ax^3}{3}-4ax+c$

$f(0)=4, \ f(2)=0\Rightarrow c=4, \ a=\frac{3}{4}$

Therefore $f(x)=\frac{1}{4}x^3-3x+4$

See the graph.

3. Originally Posted by jwbehm
Sketch a possible graph with the following characteristics

dont even know where to start. . . any help is appreciated.

thanks

Jordan
It is insulting to delete image links after getting help. Thread closed.