Originally Posted by

**arbolis** A lattice is on the portion of the disk $\displaystyle x^2+y^2 \leq 1$ in the first quadrant. Find its center of mass if the density at any point is proportional to its distance with the $\displaystyle \color{red}{x}$ axis.

My attempt : I first calculated the total mass of the lattice which gave me $\displaystyle \frac{k}{3}$, where $\displaystyle k$ is the constant of proportionality.

Then I found out that the center of mass is located at $\displaystyle \left( \frac{3}{8},\frac{3}{16} \right)$.

I just want to know if this is the correct result because I find it quite strange.