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Math Help - Sepecial "limit sequence"

  1. #1
    Super Member dhiab's Avatar
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    Sepecial "limit sequence"

    Calculate :
    Knowing :
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  2. #2
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    \frac{{}^{n} C_k}{n^k} = \frac{n!}{n^k (n-k)! k!} = \frac{n(n-1) \ldots (n-k+1)}{n^k k!}

    Now compare orders of terms in the numerator and denominator. I don't know if you have the answer to work towards, so just to give you a bit more direction here it is if you want it:

    Spoiler:
    \frac{1}{k!}


    Hope this helps.
    pomp.
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  3. #3
    Super Member dhiab's Avatar
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    Quote Originally Posted by pomp View Post
    \frac{{}^{n} C_k}{n^k} = \frac{n!}{n^k (n-k)! k!} = \frac{n(n-1) \ldots (n-k+1)}{n^k k!}

    Now compare orders of terms in the numerator and denominator. I don't know if you have the answer to work towards, so just to give you a bit more direction here it is if you want it:

    Spoiler:
    \frac{1}{k!}


    Hope this helps.
    pomp.
    Hello : Thank you I'have some details :

    The numerator is a polyniom :


    Then :
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