Calculate :http://www.mathramz.com/xyz/latexren...001b7b6920.png

Knowing :

http://www.mathramz.com/xyz/latexren...49fb53663e.png

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- Jul 18th 2009, 03:47 AMdhiabSepecial "limit sequence"
- Jul 18th 2009, 07:37 AMpomp
$\displaystyle \frac{{}^{n} C_k}{n^k} = \frac{n!}{n^k (n-k)! k!} = \frac{n(n-1) \ldots (n-k+1)}{n^k k!} $

Now compare orders of terms in the numerator and denominator. I don't know if you have the answer to work towards, so just to give you a bit more direction here it is if you want it:

__Spoiler__:

Hope this helps.

pomp. - Jul 18th 2009, 08:00 AMdhiab
**Hello : Thank you I'have some details**:

**The numerator is a polyniom**:

http://www.mathramz.com/xyz/latexren...7ec91a2b5c.png

**Then :**

http://www.mathramz.com/xyz/latexren...d276152a2c.png