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Math Help - Does the sum converge?

  1. #1
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    Does the sum converge?

    There are two different questions but I am hoping that if I get help with the first one, I will be able to do the second one on my own.

    Find the sum of the series if it converges or show that it diverges

    ∑ n=0 to infinity of [2^(3n)-1] / [ 3^(2n)]

    Do I do the nth term test and take the limit of it? I am not good at limits either.

    Thanks!
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  2. #2
    o_O
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    Is this the series? \sum_{n=0}^{\infty} \frac{2^{3n} - 1}{3^{2n}}

    In any case, note that this is equivalent to:

    = \sum_{n=0}^{\infty} \left[ \frac{\left(2^3\right)^n}{\left(3^2\right)^{n}} - \frac{1}{\left(3^2\right)^n}\right] \ = \ \sum_{n=0}^{\infty} \left[ \left( \frac{8}{9}\right)^n - \left(\frac{1}{9}\right)^n\right]

    by simple exponent rules. We can see this is a sum of two geometric series ( |r| < 1) which of course converges.
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  3. #3
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    thanks o_O. But wow, I definitely need to review my notes because that still doesn't make that much sense! I will work through what you gave me and with my notes to see if I understand it
    Thanks again!
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