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Math Help - ln help

  1. #1
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    ln help

    Y ln 5x^2
    Y'  1/5x^2 . 10x = 10x/5x^2 = 10/5x = 2^-1
    Last edited by crashuk; July 15th 2009 at 04:39 PM.
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  2. #2
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    Quote Originally Posted by crashuk View Post
    ln 5x^2
     1/5x^2 . 10x = 10x/5x^2 = 10/5x = 2^-1
    Please review your post. It is almost nonsensical due to bad presentation. There is also no question.

    I'm guesing what you meant to say was:

    Is this correct?

    \frac{d}{dx} \left( \ln{\left(5x^2 \right)} \right) = 10x \times \frac{1}{5x^2} = \frac{2}{x} ?

    If so, then yes it is.
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  3. #3
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    yes thanks, sorry about the way i post it havent a clue to do some things on line.
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  4. #4
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    That's fine, just try to make sure it's at least possible to get the gist of what you're saying. Write a little, explain what it is you are trying to do, say where you are stuck and where you need help. Simply posting 2 equations means nothing.

    You might find this useful:

    http://www.mathhelpforum.com/math-he...-tutorial.html

    It will help a lot with general mathematical formatting.
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