# Thread: Limit calculation

1. ## Limit calculation

Hey,
Can anyone please tell me why is this limit correct?

2. $\lim_{x\to 0}\frac{e^{\frac{-1}{x^{2}}}}{x}$

Let $t=\frac{1}{x^{2}}, \;\ x=\frac{1}{\sqrt{t}}$

Making the subs gives us:

$\lim_{t\to \infty}\frac{\sqrt{t}}{e^{t}}=0$

e grows much more than the radical, so it tends to 0

3. tnx.. =]