Take , so that as . Check that . So the function is not continuous at points on the parabola.
Hello again,
I have some troubles doing this exercise, it asks me to study the continuity of the following function in R2:
F(x,y) = < F1(x,y) , F2(x,y) >
Where those functions are:
F1 (x,y) = 0, if y = x^2
F1 (x,y) = (x^2+y) / (x^2-y), if y != x^2
F2 (x,y) = 0, if x^2+y^2 = 0
F2 (x,y) = (x^2-y)*sin(1/(x^2+y^2)), if x^2+y^2 != 0
Now, I suppose that the function F(x,y) is continuos for each point of R2 where both F1 and F2 are continuos. Is that ok?
Then I ve studied the continuity of those function:
F2 is continuos for each point of R2 because the only interesting point is (0,0) since this is the unique point where the condition x^2+y^2=0 become true and at this point the function seems to be continuos (using polar coordinates and r ->0).
F1 is not continuos in (0,0) since by taking 2 different paths (x,0) and (0,y) the limit isn't the same but how can I prove the continuity for all the points standing on y=x^2?
Thanks in advance!