# Thread: Derivative slope and rule of chance?

1. ## Derivative slope and rule of chance?

can any one help me with my assign?

f(x) = 2x - 3
3x + 4

2. Originally Posted by 19minkida22
can any one help me with my assign?

f(x) = 2x - 3
3x + 4

$f(x)=\frac{2x-3}{3x+4}$

write it like this

$f(x)=(2x-3)(3x+4)^{-1}$ use product rule

product rule in general

$H(x)=A(x)B(x) \Rightarrow H'(x)=A'(x)B(x)+B'(x)A(x)$ or leave it as the first form and use division rule

division rule in general

$H(x)=\frac{A(x)}{B(x)} \Rightarrow H'(x)=\frac{B(x)A'(x)-B'(x)A(x)}{(B(x))^2}$

you should try show us your answer and if there is any wrong I will correct it

3. Originally Posted by 19minkida22
can any one help me with my assign?

f(x) = 2x - 3
3x + 4
You can use the quotient rule to find the derivative

The derivative of $\frac{f}{g}$ is $\frac{f'g-fg'}{g^2}$

$f(x) = 2x-3 f'(x) = 2$
$g(x) = 3x+4 g'(x) = 3$

Can you finish it?

Good luck!