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Math Help - Derivative slope and rule of chance?

  1. #1
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    Derivative slope and rule of chance?

    can any one help me with my assign?

    f(x) = 2x - 3
    3x + 4
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  2. #2
    MHF Contributor Amer's Avatar
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    Quote Originally Posted by 19minkida22 View Post
    can any one help me with my assign?

    f(x) = 2x - 3
    3x + 4

    f(x)=\frac{2x-3}{3x+4}

    write it like this

    f(x)=(2x-3)(3x+4)^{-1} use product rule

    product rule in general

    H(x)=A(x)B(x) \Rightarrow H'(x)=A'(x)B(x)+B'(x)A(x) or leave it as the first form and use division rule

    division rule in general

    H(x)=\frac{A(x)}{B(x)} \Rightarrow H'(x)=\frac{B(x)A'(x)-B'(x)A(x)}{(B(x))^2}

    you should try show us your answer and if there is any wrong I will correct it
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  3. #3
    Senior Member apcalculus's Avatar
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    Quote Originally Posted by 19minkida22 View Post
    can any one help me with my assign?

    f(x) = 2x - 3
    3x + 4
    You can use the quotient rule to find the derivative

    The derivative of \frac{f}{g} is \frac{f'g-fg'}{g^2}

    f(x) = 2x-3 f'(x) = 2
    g(x) = 3x+4 g'(x) = 3

    Can you finish it?

    Good luck!
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