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Thread: Definite Integration:

  1. July 14th 2009, 04:44 AM #1
    newtoinequality
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    Definite Integration:

    Evaluate:

    I=\int_0^\pi\sec 2x\ dx
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  2. July 14th 2009, 05:18 AM #2
    CaptainBlack
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    Quote Originally Posted by newtoinequality View Post
    Evaluate:

    I=\int_0^\pi\sec 2x\ dx
    This does not have an integral, it is an improper integral for which a limit does not exist when the sizes of the intervals excluding the singularities shrink to 0.

    CB
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