# Math Help - Definite Integration:

1. ## Definite Integration:

Evaluate:

$I=\int_0^\pi\sec 2x\ dx$

2. Originally Posted by newtoinequality
Evaluate:

$I=\int_0^\pi\sec 2x\ dx$
This does not have an integral, it is an improper integral for which a limit does not exist when the sizes of the intervals excluding the singularities shrink to 0.

CB