# Definite Integration:

• Jul 14th 2009, 04:44 AM
newtoinequality
Definite Integration:
Evaluate:

$I=\int_0^\pi\sec 2x\ dx$
• Jul 14th 2009, 05:18 AM
CaptainBlack
Quote:

Originally Posted by newtoinequality
Evaluate:

$I=\int_0^\pi\sec 2x\ dx$

This does not have an integral, it is an improper integral for which a limit does not exist when the sizes of the intervals excluding the singularities shrink to 0.

CB