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Math Help - Implicit Differention

  1. #1
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    Implicit Differention

    Well I tried out this equation(x^3-2x^2y+3xy^2 = 38, and i got dy/dx = 4xy+3y^2/-2x^2+6xy. I know it is incorrect. Can someone walk me through this so I can correct my mistake? I'm studying for a test on monday
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  2. #2
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     x^{3} -2x^{2}y +3xy^{2} =38

     3x^{2} - 4xy - 2x^{2} \frac {dy}{dx} + 3y^{2} + 6xy \frac {dy}{dx} = 0

    now solve for  \frac {dy}{dx}
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  3. #3
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    Quote Originally Posted by sgonzalez90 View Post
    Well I tried out this equation(x^3-2x^2y+3xy^2 = 38, and i got dy/dx = 4xy+3y^2/-2x^2+6xy. I know it is incorrect. Can someone walk me through this so I can correct my mistake? I'm studying for a test on monday
    \frac{d}{dx}\left[x^3 - 2x^2y + 3xy^2 = 38\right]<br />

    3x^2 - 2x^2 \frac{dy}{dx} - 4xy + 6xy \frac{dy}{dx} + 3y^2 = 0

    \frac{dy}{dx}\left(6xy - 2x^2\right) = 4xy - 3x^2 - 3y^2

    \frac{dy}{dx} = \frac{4xy - 3x^2 - 3y^2}{6xy - 2x^2}
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